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To show the connection of the Rieman Hypothesis to the Harmonic Progression, the Zeta function, multiplication and why the zeros can't be verified.

Also why x³ + y³ cannot equal z³ .

J Roche' Wolf traxway@earthlink.net

,

To show why X³ plus Y³ cannot equal Z³ .

The Y cube would have to be distorted to fit onto the X cube.

Algorithm

Our

A Better way to factor numbers, faster.

.Connection to the Riemann Hypothesis.

To show that only four primes numbers are needed to factor all number to 120. Eleven being the next prime squared is 121. Contrary to some.

Because I had developed an algorithm for factoring numbers. And learning that the harmonic progression and the Zeta Function and the Riemann Hypothesis are connected.

ALGORITHM

Faster way to factor numbers.

Using: Mathematica

Having formulated the above Algorithm, and

having read that the Riemann Hypothesis is connected to the Harmonic Progression, the first example shows using all number less than the square root of x. Where all the candidate numbers are multiplied together, I call them "multiplex numbers". The second example uses only prime numbers.

The first question asked about the Riemann is "how is addition connected to multiplication?" (1/2+1/3+1/5) can be written as (15/30+10/30+6/30)=31/30 or (0.5+0.333+0.2)=1.033, the fraction is a more precise answer than the decimal. And is why the zeros can't be found, because of using decimals.

This might help to understand DNA.

How it works:

Best for numbers with two factors.

Check "x" the number to be factored if it is a perfect square. Multiply together all numbers less the square root of x or all numbers selected for the factoring of x, a multiplex number has been created. Divide multiplex number by x, save the remainder. Work the "remainder" and "x" against each other to find the factor or apply GCD to "x" and the remainder.

Very large number could be done in sections.

The multiplex number cannot contain all the factors of x.

Numbers with many factors will need less candidate number accordantly.

Output might not be Prime. Many variations are possible. Process might need to be repeated with output.

Why: This could be FERMATS lost Proof for : X cubed + Y cubed cannot = Z cubed.

Why (x³ + Y³ ) / (x +y) will yield a whole number.

Observe cube figures above.

x and y represent the cube root of the blue and red

cubes ( 2 and 3 ) , w=(x +y) ="5".

(x*y*w} are the brick shaped pieces.

w³ -(x³ +y³ ) =(x*y*w)*3 (* is a times symbol}

125 - (27 + 8) = ( 2*3*5 )3

125 - 35 = 90 all three numbers have a common

denominator of "5"

(x+ y)³ will always be larger than (x³ + y³ ).

Therefore (x³ +y³ ) cannot = z³ .

That is the proof !

It also works with numbers with equal odd number

exponents......5.....7.... etc.

(x⁵ +y⁵ ) / (x+ y) will yield a whole number.

Numbers with even exponents are squares.

8 = 2³ , 9 is one number from 2³ .

3 is a constant in the formula.

x=8; y=9; x

using formula ((x) (y) (y-x) 3))+(y-x)³

((8) (9) (9-8) 3))+(9-8)³ = 217 =6³ +1

8³ + 6³ +1 = 9³

That's as good as it gets.

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